Update spacy.load()

path argument is now deprecated and name can either take a model name
or path. Implement lazy loading by importing module and read Language
class name off __all__.

spacy/__init__.py

@@ -1,37 +1,23 @@
 # coding: utf8
 from __future__ import unicode_literals
 
-from . import util
-from .util import prints
-from .deprecated import resolve_model_name
 import importlib
+
+from .compat import basestring_
 from .cli.info import info
 from .glossary import explain
-
-
-_languages_name = set(["en", "de", "es", "pt", "fr",
-             "it", "hu", "zh", "nl", "sv",
-             "fi", "bn", "he", "nb", "ja"])
+from . import util
 
 
 def load(name, **overrides):
-    if overrides.get('path') in (None, False, True):
-        data_path = util.get_data_path()
-        model_name = resolve_model_name(name)
-        model_path = data_path / model_name
-        if not model_path.exists():
-            lang_name = util.get_lang_class(name).lang
-            model_path = None
-            prints("Only loading the '%s' tokenizer." % lang_name,
-                   title="Warning: no model found for '%s'" % name)
-    else:
-        model_path = util.ensure_path(overrides['path'])
-        data_path = model_path.parent
-        model_name = ''
-    meta = util.parse_package_meta(data_path, model_name, require=False)
-    lang = meta['lang'] if meta and 'lang' in meta else name
-    module = importlib.import_module("."+lang, "spacy")
-    cls = module.EXPORT
+    if overrides.get('path') not in (None, False, True):
+        name = overrides.get('path')
+    model_path = util.resolve_model_path(name)
+    meta = util.parse_package_meta(model_path)
+    if 'lang' not in meta:
+        raise IOError('No language setting found in model meta.')
+    module = importlib.import_module('.%s' % meta['lang'], 'spacy')
+    cls = getattr(module, module.__all__[0])
     overrides['meta'] = meta
     overrides['path'] = model_path
     return cls(**overrides)