#from: http://stackoverflow.com/questions/19367488/converting-function-to-numbapro-cuda
#setup: N = 10 ; import numpy ; a = numpy.random.rand(N,N)
#run: fdtd(a,10)

#pythran export fdtd(float[][], int)
import numpy as np

def fdtd(input_grid, steps):
    grid = input_grid.copy()
    old_grid = np.zeros_like(input_grid)
    previous_grid = np.zeros_like(input_grid)

    l_x = grid.shape[0]
    l_y = grid.shape[1]

    for i in range(steps):
        np.copyto(previous_grid, old_grid)
        np.copyto(old_grid, grid)

        for x in range(l_x):
            for y in range(l_y):
                grid[x,y] = 0.0
                if 0 < x+1 < l_x:
                    grid[x,y] += old_grid[x+1,y]
                if 0 < x-1 < l_x:
                    grid[x,y] += old_grid[x-1,y]
                if 0 < y+1 < l_y:
                    grid[x,y] += old_grid[x,y+1]
                if 0 < y-1 < l_y:
                    grid[x,y] += old_grid[x,y-1]

                grid[x,y] /= 2.0
                grid[x,y] -= previous_grid[x,y]

    return grid