Shield newline symbol when generating labels for graphviz
Python converts '\n' to actual newline before putting it into dot format. Although the previous approach somehow works it's better to pass '\n' explicitly.
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@ -594,19 +594,19 @@ def dump_graphviz(tree, output_format='dot', is_reverse=False):
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if not is_reverse:
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if not is_reverse:
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for pkg, deps in tree.items():
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for pkg, deps in tree.items():
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pkg_label = '{0}\n{1}'.format(pkg.project_name, pkg.version)
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pkg_label = '{0}\\n{1}'.format(pkg.project_name, pkg.version)
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graph.node(pkg.key, label=pkg_label)
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graph.node(pkg.key, label=pkg_label)
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for dep in deps:
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for dep in deps:
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edge_label = dep.version_spec or 'any'
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edge_label = dep.version_spec or 'any'
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if dep.is_missing:
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if dep.is_missing:
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dep_label = '{0}\n(missing)'.format(dep.project_name)
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dep_label = '{0}\\n(missing)'.format(dep.project_name)
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graph.node(dep.key, label=dep_label, style='dashed')
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graph.node(dep.key, label=dep_label, style='dashed')
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graph.edge(pkg.key, dep.key, style='dashed')
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graph.edge(pkg.key, dep.key, style='dashed')
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else:
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else:
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graph.edge(pkg.key, dep.key, label=edge_label)
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graph.edge(pkg.key, dep.key, label=edge_label)
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else:
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else:
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for dep, parents in tree.items():
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for dep, parents in tree.items():
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dep_label = '{0}\n{1}'.format(dep.project_name,
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dep_label = '{0}\\n{1}'.format(dep.project_name,
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dep.installed_version)
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dep.installed_version)
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graph.node(dep.key, label=dep_label)
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graph.node(dep.key, label=dep_label)
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for parent in parents:
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for parent in parents:
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