import string import re import sys # Reason last stmt is continued (or C_NONE if it's not). C_NONE, C_BACKSLASH, C_STRING, C_BRACKET = range(4) if 0: # for throwaway debugging output def dump(*stuff): import sys sys.__stdout__.write(string.join(map(str, stuff), " ") + "\n") # find a def or class stmt _defclassre = re.compile(r""" ^ [ \t]* (?: def [ \t]+ [a-zA-Z_]\w* [ \t]* \( | class [ \t]+ [a-zA-Z_]\w* [ \t]* (?: \( .* \) )? [ \t]* : ) """, re.VERBOSE | re.MULTILINE).search # match blank line or non-indenting comment line _junkre = re.compile(r""" [ \t]* (?: \# [^ \t\n] .* )? \n """, re.VERBOSE).match # match any flavor of string; the terminating quote is optional # so that we're robust in the face of incomplete program text _match_stringre = re.compile(r""" \""" [^"\\]* (?: (?: \\. | "(?!"") ) [^"\\]* )* (?: \""" )? | " [^"\\\n]* (?: \\. [^"\\\n]* )* "? | ''' [^'\\]* (?: (?: \\. | '(?!'') ) [^'\\]* )* (?: ''' )? | ' [^'\\\n]* (?: \\. [^'\\\n]* )* '? """, re.VERBOSE | re.DOTALL).match # match a line that doesn't start with something interesting; # used to skip junk lines when searching for the first element # of a bracket structure _not_itemre = re.compile(r""" [ \t]* [#\n\\] """, re.VERBOSE).match # match start of stmts that should be followed by a dedent _closere = re.compile(r""" \s* (?: return | break | continue | raise | pass ) \b """, re.VERBOSE).match # Build translation table to map uninteresting chars to "x", open # brackets to "(", and close brackets to ")". _tran = ['x'] * 256 for ch in "({[": _tran[ord(ch)] = '(' for ch in ")}]": _tran[ord(ch)] = ')' for ch in "\"'\\\n#": _tran[ord(ch)] = ch _tran = string.join(_tran, '') del ch class Parser: def __init__(self, indentwidth, tabwidth): self.indentwidth = indentwidth self.tabwidth = tabwidth def set_str(self, str): assert len(str) == 0 or str[-1] == '\n' self.str = str self.study_level = 0 # Return index of start of last (probable!) def or class stmt, or # None if none found. It's only probable because we can't know # whether we're in a string without reparsing from the start of # the file -- and that's too slow to bear. # # Ack, hack: in the shell window this kills us, because there's # no way to tell the differences between output, >>> etc and # user input. Indeed, IDLE's first output line makes the rest # look like it's in an unclosed paren!: # Python 1.5.2 (#0, Apr 13 1999, ... def find_last_def_or_class(self, _defclassre=_defclassre): str, pos = self.str, None i = 0 while 1: m = _defclassre(str, i) if m: pos, i = m.span() else: break if pos is None: # hack for shell window ps1 = '\n' + sys.ps1 i = string.rfind(str, ps1) if i >= 0: pos = i + len(ps1) self.str = str[:pos-1] + '\n' + str[pos:] return pos # Throw away the start of the string. Intended to be called with # find_last_def_or_class's result. def set_lo(self, lo): assert lo == 0 or self.str[lo-1] == '\n' if lo > 0: self.str = self.str[lo:] # As quickly as humanly possible , find the line numbers (0- # based) of the non-continuation lines. # Creates self.{stmts, continuation}. def _study1(self, _replace=string.replace, _find=string.find): if self.study_level >= 1: return self.study_level = 1 # Map all uninteresting characters to "x", all open brackets # to "(", all close brackets to ")", then collapse runs of # uninteresting characters. This can cut the number of chars # by a factor of 10-40, and so greatly speed the following loop. str = self.str str = string.translate(str, _tran) str = _replace(str, 'xxxxxxxx', 'x') str = _replace(str, 'xxxx', 'x') str = _replace(str, 'xx', 'x') str = _replace(str, 'xx', 'x') str = _replace(str, '\nx', '\n') # note that replacing x\n with \n would be incorrect, because # x may be preceded by a backslash # March over the squashed version of the program, accumulating # the line numbers of non-continued stmts, and determining # whether & why the last stmt is a continuation. continuation = C_NONE level = lno = 0 # level is nesting level; lno is line number self.stmts = stmts = [0] push_stmt = stmts.append i, n = 0, len(str) while i < n: ch = str[i] # cases are checked in decreasing order of frequency if ch == 'x': i = i+1 continue if ch == '\n': lno = lno + 1 if level == 0: push_stmt(lno) # else we're in an unclosed bracket structure i = i+1 continue if ch == '(': level = level + 1 i = i+1 continue if ch == ')': if level: level = level - 1 # else the program is invalid, but we can't complain i = i+1 continue if ch == '"' or ch == "'": # consume the string quote = ch if str[i:i+3] == quote * 3: quote = quote * 3 w = len(quote) i = i+w while i < n: ch = str[i] if ch == 'x': i = i+1 continue if str[i:i+w] == quote: i = i+w break if ch == '\n': lno = lno + 1 i = i+1 if w == 1: # unterminated single-quoted string if level == 0: push_stmt(lno) break continue if ch == '\\': assert i+1 < n if str[i+1] == '\n': lno = lno + 1 i = i+2 continue # else comment char or paren inside string i = i+1 else: # didn't break out of the loop, so it's an # unterminated triple-quoted string assert w == 3 continuation = C_STRING continue if ch == '#': # consume the comment i = _find(str, '\n', i) assert i >= 0 continue assert ch == '\\' assert i+1 < n if str[i+1] == '\n': lno = lno + 1 if i+2 == n: continuation = C_BACKSLASH i = i+2 # Push the final line number as a sentinel value, regardless of # whether it's continued. if stmts[-1] != lno: push_stmt(lno) # The last stmt may be continued for all 3 reasons. # String continuation takes precedence over bracket # continuation, which beats backslash continuation. if continuation != C_STRING and level > 0: continuation = C_BRACKET self.continuation = continuation def get_continuation_type(self): self._study1() return self.continuation # study1 was sufficient to determine the continuation status, # but doing more requires looking at every character. study2 # does this for the last interesting statement in the block. # Creates: # self.stmt_start, stmt_end # slice indices of last interesting stmt # self.lastch # last non-whitespace character before optional trailing # comment # self.lastopenbracketpos # if continuation is C_BRACKET, index of last open bracket def _study2(self, _rfind=string.rfind, _find=string.find, _ws=string.whitespace): if self.study_level >= 2: return self._study1() self.study_level = 2 self.lastch = "" # Set p and q to slice indices of last interesting stmt. str, stmts = self.str, self.stmts i = len(stmts) - 1 p = len(str) # index of newest line found = 0 while i: assert p # p is the index of the stmt at line number stmts[i]. # Move p back to the stmt at line number stmts[i-1]. q = p for nothing in range(stmts[i-1], stmts[i]): # tricky: sets p to 0 if no preceding newline p = _rfind(str, '\n', 0, p-1) + 1 # The stmt str[p:q] isn't a continuation, but may be blank # or a non-indenting comment line. if _junkre(str, p): i = i-1 else: found = 1 break self.stmt_start, self.stmt_end = p, q # Analyze this stmt, to find the last open bracket (if any) # and last interesting character (if any). stack = [] # stack of open bracket indices push_stack = stack.append while p < q: ch = str[p] if ch == '"' or ch == "'": # consume string # Note that study1 did this with a Python loop, but # we use a regexp here; the reason is speed in both # cases; the string may be huge, but study1 pre-squashed # strings to a couple of characters per line. study1 # also needed to keep track of newlines, and we don't # have to. self.lastch = ch p = _match_stringre(str, p, q).end() continue if ch == '#': # consume comment and trailing newline p = _find(str, '\n', p, q) + 1 assert p > 0 continue if ch == '\\': assert p+1 < q if str[p+1] != '\n': # the program is invalid, but can't complain self.lastch = str[p:p+2] p = p+2 continue if ch not in _ws: self.lastch = ch if ch in "([{": push_stack(p) elif ch in ")]}" and stack: del stack[-1] p = p+1 # end while p < q: if stack: self.lastopenbracketpos = stack[-1] # Assuming continuation is C_BRACKET, return the number # of spaces the next line should be indented. def compute_bracket_indent(self, _find=string.find): self._study2() assert self.continuation == C_BRACKET j = self.lastopenbracketpos str = self.str n = len(str) origi = i = string.rfind(str, '\n', 0, j) + 1 j = j+1 # find first list item while _not_itemre(str, j): # this line is junk; advance to the next line i = _find(str, '\n', j) if i < 0: break j = i = i+1 if i < 0 or j >= n: # nothing interesting follows the bracket; # reproduce the bracket line's indentation + a level j = i = origi extra = self.indentwidth else: # the first list item begins on this line; line up with # the first interesting character extra = 0 while str[j] in " \t": j = j+1 return len(string.expandtabs(str[i:j], self.tabwidth)) + extra # Return number of physical lines in last stmt (whether or not # it's an interesting stmt! this is intended to be called when # continuation is C_BACKSLASH). def get_num_lines_in_stmt(self): self._study1() stmts = self.stmts return stmts[-1] - stmts[-2] # Assuming continuation is C_BACKSLASH, return the number of spaces # the next line should be indented. Also assuming the new line is # the first one following the initial line of the stmt. def compute_backslash_indent(self): self._study2() assert self.continuation == C_BACKSLASH str = self.str i = self.stmt_start while str[i] in " \t": i = i+1 startpos = i endpos = string.find(str, '\n', startpos) + 1 found = level = 0 while i < endpos: ch = str[i] if ch in "([{": level = level + 1 i = i+1 elif ch in ")]}": if level: level = level - 1 i = i+1 elif ch == '"' or ch == "'": i = _match_stringre(str, i, endpos).end() elif ch == '#': break elif level == 0 and ch == '=' and \ (i == 0 or str[i-1] not in "=<>!") and \ str[i+1] != '=': found = 1 break else: i = i+1 if found: # found a legit =, but it may be the last interesting # thing on the line i = i+1 # move beyond the = found = re.match(r"\s*\\", str[i:endpos]) is None if not found: # oh well ... settle for moving beyond the first chunk # of non-whitespace chars i = startpos while str[i] not in " \t\n": i = i+1 return len(string.expandtabs(str[self.stmt_start : i], self.tabwidth)) + 1 # Return the leading whitespace on the initial line of the last # interesting stmt. def get_base_indent_string(self): self._study2() i, n = self.stmt_start, self.stmt_end assert i is not None j = i str = self.str while j < n and str[j] in " \t": j = j + 1 return str[i:j] # Did the last interesting stmt open a block? def is_block_opener(self): self._study2() return self.lastch == ':' # Did the last interesting stmt close a block? def is_block_closer(self): self._study2() return _closere(self.str, self.stmt_start) is not None