Fix SF bug #637789: Handle Proxy-Connection header.

Also, remove unused local variable noted by pychecker.
This commit is contained in:
Jeremy Hylton 2002-11-13 17:27:43 +00:00
parent 33635aaf93
commit 22b3a49d3c
1 changed files with 25 additions and 15 deletions

View File

@ -169,7 +169,6 @@ def readheaders(self):
# for http and/or for repeating headers
# It's a continuation line.
list.append(line)
x = self.dict[headerseen] + "\n " + line.strip()
self.addcontinue(headerseen, line.strip())
continue
elif self.iscomment(line):
@ -311,20 +310,7 @@ def begin(self):
self.chunked = 0
# will the connection close at the end of the response?
conn = self.msg.getheader('connection')
if conn:
conn = conn.lower()
# a "Connection: close" will always close the connection. if we
# don't see that and this is not HTTP/1.1, then the connection will
# close unless we see a Keep-Alive header.
self.will_close = conn.find('close') != -1 or \
( self.version != 11 and \
not self.msg.getheader('keep-alive') )
else:
# for HTTP/1.1, the connection will always remain open
# otherwise, it will remain open IFF we see a Keep-Alive header
self.will_close = self.version != 11 and \
not self.msg.getheader('keep-alive')
self.will_close = self._check_close()
# do we have a Content-Length?
# NOTE: RFC 2616, S4.4, #3 says we ignore this if tr_enc is "chunked"
@ -351,6 +337,30 @@ def begin(self):
self.length is None:
self.will_close = 1
def _check_close(self):
if self.version == 11:
# An HTTP/1.1 proxy is assumed to stay open unless
# explicitly closed.
conn = self.msg.getheader('connection')
if conn and conn.lower().find("close") >= 0:
return True
return False
# An HTTP/1.0 response with a Connection header is probably
# the result of a confused proxy. Ignore it.
# For older HTTP, Keep-Alive indiciates persistent connection.
if self.msg.getheader('keep-alive'):
return False
# Proxy-Connection is a netscape hack.
pconn = self.msg.getheader('proxy-connection')
if pconn and pconn.lower().find("keep-alive") >= 0:
return False
# otherwise, assume it will close
return True
def close(self):
if self.fp:
self.fp.close()