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svn+ssh://pythondev@svn.python.org/python/branches/py3k ........ r82899 | senthil.kumaran | 2010-07-15 02:00:02 +0530 (Thu, 15 Jul 2010) | 2 lines Fix issue9132 - Documentation for comparing dictionaries is out of date ........
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@ -1026,9 +1026,9 @@ Comparison of objects of the same type depends on the type:
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``x <= y``. If the corresponding element does not exist, the shorter
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sequence is ordered first (for example, ``[1,2] < [1,2,3]``).
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* Mappings (dictionaries) compare equal if and only if their sorted ``(key,
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value)`` lists compare equal. [#]_ Outcomes other than equality are resolved
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consistently, but are not otherwise defined. [#]_
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* Mappings (dictionaries) compare equal if and only if they have the same
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``(key, value)`` pairs. Order comparisons ``('<', '<=', '>=', '>')``
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raise :exc:`TypeError`.
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* Sets and frozensets define comparison operators to mean subset and superset
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tests. Those relations do not define total orderings (the two sets ``{1,2}``
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@ -1310,15 +1310,6 @@ groups from right to left).
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strings in a human recognizable way, compare using
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:func:`unicodedata.normalize`.
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.. [#] The implementation computes this efficiently, without constructing lists
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or sorting.
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.. [#] Earlier versions of Python used lexicographic comparison of the sorted (key,
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value) lists, but this was very expensive for the common case of comparing
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for equality. An even earlier version of Python compared dictionaries by
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identity only, but this caused surprises because people expected to be able
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to test a dictionary for emptiness by comparing it to ``{}``.
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.. [#] Due to automatic garbage-collection, free lists, and the dynamic nature of
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descriptors, you may notice seemingly unusual behaviour in certain uses of
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the :keyword:`is` operator, like those involving comparisons between instance
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