cpython/Tools/freeze/checkextensions.py

# Check for a module in a set of extension directories.
# An extension directory should contain a Setup file
# and one or more .o files or a lib.a file.

import os
import string
import parsesetup

def checkextensions(unknown, extensions):
	files = []
	modules = []
	edict = {}
	for e in extensions:
		setup = os.path.join(e, 'Setup')
		liba = os.path.join(e, 'lib.a')
		if not os.path.isfile(liba):
			liba = None
		edict[e] = parsesetup.getsetupinfo(setup), liba
	for mod in unknown:
		for e in extensions:
			(mods, vars), liba = edict[e]
			if not mods.has_key(mod):
				continue
			modules.append(mod)
			if liba:
				# If we find a lib.a, use it, ignore the
				# .o files, and use *all* libraries for
				# *all* modules in the Setup file
				if liba in files:
					break
				files.append(liba)
				for m in mods.keys():
					files = files + select(e, mods, vars,
							       m, 1)
				break
			files = files + select(e, mods, vars, mod, 0)
			break
	return files, modules

def select(e, mods, vars, mod, skipofiles):
	files = []
	for w in mods[mod]:
		w = treatword(w)
		if not w:
			continue
		w = expandvars(w, vars)
		for w in string.split(w):
			if skipofiles and w[-2:] == '.o':
				continue
			if w[0] != '-' and w[-2:] in ('.o', '.a'):
				w = os.path.join(e, w)
			if w[:2] in ('-L', '-R'):
				w = w[:2] + os.path.join(e, w[2:])
			files.append(w)
	return files

cc_flags = ['-I', '-D', '-U']
cc_exts = ['.c', '.C', '.cc', '.c++']

def treatword(w):
	if w[:2] in cc_flags:
		return None
	if w[:1] == '-':
		return w # Assume loader flag
	head, tail = os.path.split(w)
	base, ext = os.path.splitext(tail)
	if ext in cc_exts:
		tail = base + '.o'
		w = os.path.join(head, tail)
	return w

def expandvars(str, vars):
	i = 0
	while i < len(str):
		i = k = string.find(str, '$', i)
		if i < 0:
			break
		i = i+1
		var = str[i:i+1]
		i = i+1
		if var == '(':
			j = string.find(str, ')', i)
			if j < 0:
				break
			var = str[i:j]
			i = j+1
		if vars.has_key(var):
			str = str[:k] + vars[var] + str[i:]
			i = k
	return str