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@ -70,20 +70,27 @@ resource share.
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<p>
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<p>
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For example, consider a system participating in two projects, A and B,
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For example, consider a system participating in two projects, A and B,
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with resource shares 75% and 25%, respectively.
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with resource shares 75% and 25%, respectively.
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Suppose in some time period, the system devotes 25 minutes of CPU time to project A
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Suppose in some time period, the system devotes 25 minutes of CPU time to
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and 15 minutes of CPU time to project B.
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project A and 15 minutes of CPU time to project B.
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We decrease the debt to A by 25 minutes and increase it by 30 minutes (75% of 25 + 15).
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We decrease the debt to A by 25 minutes and increase it by 30 minutes (75%
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of 25 + 15).
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So the debt increases overall.
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So the debt increases overall.
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This makes sense because we expected to devote a
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This makes sense because we expected to devote a larger percentage of the
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larger percentage of the system resources to project A than it
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system resources to project A than it actually got.
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actually got.
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<p>
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<p>
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The choice of projects for which to start result computations
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The choice of projects for which to start result computations can simply
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can simply follow the debt ordering of the projects.
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follow the debt ordering of the projects.
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The algorithm computes the 'anticipated debt' to a project
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The algorithm computes the 'anticipated debt' to a project (the debt we
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(the debt we expect to owe after the time period expires)
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expect to owe after the time period expires) as it chooses result
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as it chooses result computations to run.
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computations to run.
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<p>
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If a project has no runnable results, its resource share should not be
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considered when determining the debts for other projects.
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Furthermore, such a project should not be allowed to build-up debt while it
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has no work.
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Thus, its debt should be reset to zero.
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<h3>A sketch of the CPU scheduling algorithm</h3>
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<h3>A sketch of the CPU scheduling algorithm</h3>
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@ -109,26 +116,46 @@ property, but we hope it will be close to achieving it.
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<ol>
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<ol>
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<li>Decrease debts to projects according to the amount of work done for
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<li>
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If a project has no runnable results:
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<ol>
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<li>
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Reset its debt to 0, and do not consider its resource share to
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determine relative resource shares.
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</ol>
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<li>
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Else:
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<ol>
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<li>
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Decrease debts to projects according to the amount of work done for
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the projects in the last period.
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the projects in the last period.
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<li>
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Increase debts to projects according to the projects' relative resource
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shares.
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</ol>
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<li>Increase debts to projects according to the projects' resource shares.
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<li>
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Let the anticipated debt for each project be initialized to its current
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debt.
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<li>Let the anticipated debt for each project be initialized to
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<li>
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its current debt.
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Repeat until we decide on a result to compute for each processor:
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<li>Repeat until we decide on a result to compute for each processor:
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<ol>
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<ol>
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<li>Choose the project that has the largest anticipated debt and a
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<li>
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Choose the project that has the largest anticipated debt and a
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ready-to-compute result.
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ready-to-compute result.
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<li>Decrease the anticipated debt of the project by the expected amount of CPU time.
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<li>
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Decrease the anticipated debt of the project by the expected amount of CPU
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time.
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</ol>
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</ol>
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<li>Preempt current result computations, and start new ones.
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<li>
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Preempt current result computations, and start new ones.
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</ol>
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</ol>
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@ -161,8 +188,16 @@ foreach task T that is RUNNING:
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total_work_done_this_period += x
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total_work_done_this_period += x
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foreach P in projects:
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foreach P in projects:
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P.debt += P.resource_share * total_work_done_this_period
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if P has a runnable result:
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- P.work_done_this_period
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adjusted_total_resource_share += P.resource_share
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foreach P in projects:
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if P has no runnable result:
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P.debt = 0
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else:
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P.debt += (P.resource_share / adjusted_total_resource_share)
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* total_work_done_this_period
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- P.work_done_this_period
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expected_pay_off = total_work_done_this_period / num_cpus
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expected_pay_off = total_work_done_this_period / num_cpus
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@ -235,7 +270,7 @@ between T and 2T days from now.
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At a given time, the CPU scheduler may need as many as
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At a given time, the CPU scheduler may need as many as
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<blockquote>
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<blockquote>
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min_results(P) = ceil(ncpus * P.resource_share)
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min_results(P) = ceil(ncpus * P.resource_share / total_resource_share)
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</blockquote>
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</blockquote>
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<p>
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<p>
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@ -296,7 +331,8 @@ estimated_cpu_time(R_1, R_2, ..., R_N-k) / avg_proc_rate(P)
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where avg_proc_rate(P) is the average number of CPU seconds completed by
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where avg_proc_rate(P) is the average number of CPU seconds completed by
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the client for project P in a second of (wall-clock) time:
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the client for project P in a second of (wall-clock) time:
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<blockquote>
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<blockquote>
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avg_proc_rate(P) = P.resource_share * ncpus * 'active fraction'.
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avg_proc_rate(P) = P.resource_share / total_resource_share * ncpus *
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'active fraction'.
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</blockquote>
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</blockquote>
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<h3>How much work to get</h3>
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<h3>How much work to get</h3>
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@ -379,8 +415,11 @@ data structures:
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PROJECT:
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PROJECT:
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double work_request
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double work_request
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total_resource_share = sum of all projects' resource_share
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avg_proc_rate(P):
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avg_proc_rate(P):
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return P.resource_share * ncpus * time_stats.active_frac
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return P.resource_share / total_resource_share
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* ncpus * time_stats.active_frac
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ettprc(P, k):
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ettprc(P, k):
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results_to_skip = k
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results_to_skip = k
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