bidict/docs/orderedbidict.doctest.rst.inc

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orderedbidict
-------------
For those times when your one-to-one mapping must also support
remembering the order in which items were inserted
à la :class:`collections.OrderedDict`,
:class:`orderedbidict <bidict.orderedbidict>` and friends have got your back::
>>> from bidict import orderedbidict
>>> element_by_symbol = orderedbidict([('H', 'hydrogen'), ('He', 'helium'), ('Li', 'lithium')])
>>> element_by_symbol.inv
orderedbidict([('hydrogen', 'H'), ('helium', 'He'), ('lithium', 'Li')])
>>> first, second, third = element_by_symbol.values()
>>> first
'hydrogen'
>>> second
'helium'
>>> third
'lithium'
>>> element_by_symbol.inv['beryllium'] = 'Be'
>>> last = next(reversed(element_by_symbol))
>>> last
'Be'
The additional methods of :class:`collections.OrderedDict` are supported too::
>>> element_by_symbol.popitem(last=True)
('Be', 'beryllium')
>>> element_by_symbol.popitem(last=False)
('H', 'hydrogen')
>>> element_by_symbol['H'] = 'hydrogen'
>>> # Python 3.2+ only:
>>> element_by_symbol.move_to_end('H', last=False) # doctest: +SKIP
>>> element_by_symbol # doctest: +SKIP
orderedbidict([('H', 'hydrogen'), ('He', 'helium'), ('Li', 'lithium')])
As with :class:`collections.OrderedDict`,
equality tests between ordered bidicts are order-sensitive.
Equality tests between ordered bidicts and order-insensitive
:class:`collections.abc.Mapping` objects
are order-insensitive.
>>> ob1 = orderedbidict([('one', 1), ('two', 2)])
>>> ob2 = orderedbidict([('two', 2), ('one', 1)])
>>> ob1 == ob2
False
>>> from bidict import bidict
>>> ob1 == bidict(ob2)
True
:class:`orderedbidict <bidict.orderedbidict>` also comes in
:class:`loose <bidict.looseorderedbidict>` and
:class:`frozen <bidict.frozenorderedbidict>`
flavors.