bidict/docs/orderedbidict.rst.inc

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:class:`~bidict.OrderedBidict`
------------------------------
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For those times when your one-to-one mapping must also support
remembering the order in which items were inserted
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(à la :class:`collections.OrderedDict`),
:class:`bidict.OrderedBidict` has got your back::
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>>> from bidict import OrderedBidict
>>> element_by_symbol = OrderedBidict([
... ('H', 'hydrogen'), ('He', 'helium'), ('Li', 'lithium')])
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>>> element_by_symbol.inv
OrderedBidict([('hydrogen', 'H'), ('helium', 'He'), ('lithium', 'Li')])
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>>> first, second, third = element_by_symbol.values()
>>> first, second, third
('hydrogen', 'helium', 'lithium')
>>> # Insert an additional item and verify it now comes last:
>>> element_by_symbol['Be'] = 'beryllium'
>>> last_item = list(element_by_symbol.items())[-1]
>>> last_item
('Be', 'beryllium')
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The additional methods of :class:`~collections.OrderedDict` are supported too::
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>>> element_by_symbol.popitem(last=True) # Remove the last inserted item
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('Be', 'beryllium')
>>> element_by_symbol.popitem(last=False) # Remove the first inserted item
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('H', 'hydrogen')
>>> # Re-adding hydrogen after it's been removed moves it to the last item:
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>>> element_by_symbol['H'] = 'hydrogen'
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>>> element_by_symbol
OrderedBidict([('He', 'helium'), ('Li', 'lithium'), ('H', 'hydrogen')])
>>> # But there's also a `move_to_end` method just for this purpose:
>>> element_by_symbol.move_to_end('Li')
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>>> element_by_symbol
OrderedBidict([('He', 'helium'), ('H', 'hydrogen'), ('Li', 'lithium')])
>>> element_by_symbol.move_to_end('H', last=False) # move to front
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>>> element_by_symbol
OrderedBidict([('H', 'hydrogen'), ('He', 'helium'), ('Li', 'lithium')])
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As with :class:`~collections.OrderedDict`,
updating an existing item preserves its position in the order::
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>>> element_by_symbol['He'] = 'updated in place!'
>>> element_by_symbol
OrderedBidict([('H', 'hydrogen'), ('He', 'updated in place!'), ('Li', 'lithium')])
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When setting an item whose key duplicates that of an existing item
and whose value duplicates that of a *different* existing item,
the existing item whose *value* is duplicated will be dropped,
and the existing item whose *key* is duplicated
will have its value overwritten in place::
>>> o = OrderedBidict([(1, 2), (3, 4), (5, 6), (7, 8)])
>>> o.forceput(3, 8) # item with duplicated value (7, 8) is dropped...
>>> o # and the item with duplicated key (3, 4) is updated in place:
OrderedBidict([(1, 2), (3, 8), (5, 6)])
>>> # (3, 8) took the place of (3, 4), not (7, 8)
>>> o = OrderedBidict([(1, 2), (3, 4), (5, 6), (7, 8)]) # as before
>>> o.forceput(5, 2) # another example
>>> o
OrderedBidict([(3, 4), (5, 2), (7, 8)])
>>> # (5, 2) took the place of (5, 6), not (1, 2)
.. _eq-order-insensitive:
:meth:`~bidict.FrozenOrderedBidict.__eq__` is order-insensitive
###############################################################
To ensure that equality of bidicts is transitive
(enabling conformance to the
`Liskov substitution principle <https://en.wikipedia.org/wiki/Liskov_substitution_principle>`_),
equality tests between an ordered bidict and other
:class:`~collections.abc.Mapping`\s
are always order-insensitive::
>>> from bidict import bidict
>>> b = bidict([('one', 1), ('two', 2)])
>>> o1 = OrderedBidict([('one', 1), ('two', 2)])
>>> o2 = OrderedBidict([('two', 2), ('one', 1)])
>>> b == o1
True
>>> b == o2
True
>>> o1 == o2
True
For order-sensitive equality tests, use
:meth:`~bidict.FrozenOrderedBidict.equals_order_sensitive`::
>>> o1.equals_order_sensitive(o2)
False
>>> from collections import OrderedDict
>>> od = OrderedDict(o2)
>>> o1.equals_order_sensitive(od)
False
Note that this differs from the behavior of
:class:`collections.OrderedDict`\'s ``__eq__()``,
by recommendation of Raymond Hettinger (the author) himself
(who said that making OrderedDict's ``__eq__()``
intransitive was a mistake).
:class:`~bidict.OrderedBidict` also comes in a frozen flavor.
See the :class:`~bidict.FrozenOrderedBidict`
API documentation for more information.